Who won Iowa in the 1936 presidential election?

Roosevelt (Democratic) carried Iowa in 1936, winning its 11 electoral votes.

How many electoral votes did Iowa have in 1936?

Iowa cast 11 electoral votes in the 1936 presidential election.

Did Iowa vote for the national winner in 1936?

Yes. Iowa backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionIA · 11 EV

1936

Iowa: Roosevelt carries 11 EV.

Iowa cast its 11 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Iowa voted with the national winner this cycle.

Iowa in 1936

The 1936 contest saw Iowa line up behind Roosevelt, delivering 11 electoral votes to the Democratic ticket. That placed Iowa with the eventual winner: Franklin D. Roosevelt went on to take the presidency, and Iowa was part of his column.

Iowa stayed in the Democratic column for the 2nd straight cycle, extending a run that began in 1932. Iowa did not move alone — neighboring Minnesota, Wisconsin, Illinois, Missouri, Nebraska, and South Dakota broke the same way in 1936. Over its 47 recorded presidential cycles, Iowa has backed the Republican party more than any other — 32 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Franklin D. Roosevelt finished with 523 of the 531 electoral votes to Alf Landon's 8. Franklin D. Roosevelt led the national popular vote with 60.8% of the ballots cast.

The 1936 national map

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