Who won Iowa in the 1940 presidential election?

Willkie (Republican) carried Iowa in 1940, winning its 11 electoral votes.

How many electoral votes did Iowa have in 1940?

Iowa cast 11 electoral votes in the 1940 presidential election.

Did Iowa vote for the national winner in 1940?

No. Iowa backed Willkie, while Franklin D. Roosevelt won the presidency nationally.

New Deal CoalitionIA · 11 EV

1940

Iowa: Willkie carries 11 EV.

Iowa cast its 11 electoral votes for Willkie (Republican). National winner: Franklin D. Roosevelt (Democratic) — Iowa voted against the national winner this cycle.

What happened in Iowa, 1940

In 1940, Iowa awarded its 11 electoral votes to Willkie of the Republican party. Nationally the result broke the other way — Franklin D. Roosevelt (Democratic) won the presidency, leaving Iowa among the states he did not carry.

Willkie's win closed out Iowa's 2-election run of voting Democratic. The region divided — Nebraska and South Dakota joined Iowa for the Republican ticket, while Minnesota, Wisconsin, Illinois, and Missouri did not. Across the 47 presidential elections Iowa has taken part in, it has most often sided with the Republican party (32 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Franklin D. Roosevelt took 449 of the 531 electoral votes, against Wendell Willkie's 82. Franklin D. Roosevelt led the national popular vote with 54.74% of the ballots cast.

The 1940 national map

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