Who won Iowa in the 1956 presidential election?

Eisenhower (Republican) carried Iowa in 1956, winning its 10 electoral votes.

How many electoral votes did Iowa have in 1956?

Iowa cast 10 electoral votes in the 1956 presidential election.

Did Iowa vote for the national winner in 1956?

Yes. Iowa backed Dwight D. Eisenhower, who won the presidency that year.

New Deal CoalitionIA · 10 EV

1956

Iowa: Eisenhower carries 10 EV.

Iowa cast its 10 electoral votes for Eisenhower (Republican). National winner: Dwight D. Eisenhower (Republican) — Iowa voted with the national winner this cycle.

Reading the 1956 result in Iowa

Iowa backed Eisenhower (Republican) in the 1956 presidential election, casting 10 electoral votes for the ticket. That placed Iowa with the eventual winner: Dwight D. Eisenhower went on to take the presidency, and Iowa was part of his column.

Iowa stayed in the Republican column for the 2nd straight cycle, extending a run that began in 1952. The region divided — Wisconsin, Illinois, Nebraska, and South Dakota joined Iowa for the Republican ticket, while Minnesota and Missouri did not. Over its 47 recorded presidential cycles, Iowa has backed the Republican party more than any other — 32 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Dwight D. Eisenhower finished with 457 of the 531 electoral votes to Adlai Stevenson II's 73. Dwight D. Eisenhower led the national popular vote with 57.37% of the ballots cast.

The 1956 national map

Iowa full history →