Who won Missouri in the 1852 presidential election?

Pierce (Democratic) carried Missouri in 1852, winning its 9 electoral votes.

How many electoral votes did Missouri have in 1852?

Missouri cast 9 electoral votes in the 1852 presidential election.

Did Missouri vote for the national winner in 1852?

Yes. Missouri backed Franklin Pierce, who won the presidency that year.

Second Party SystemMO · 9 EV

1852

Missouri: Pierce carries 9 EV.

Missouri cast its 9 electoral votes for Pierce (Democratic). National winner: Franklin Pierce (Democratic) — Missouri voted with the national winner this cycle.

Reading the 1852 result in Missouri

Missouri backed Pierce (Democratic) in the 1852 presidential election, casting 9 electoral votes for the ticket. Missouri ended up on the winning side — Franklin Pierce captured the White House that year.

It marked the 7th consecutive election in which Missouri backed the Democratic party, a streak reaching back to 1828. The region divided — Iowa, Illinois, and Arkansas joined Missouri for the Democratic ticket, while Kentucky and Tennessee did not. Across the 52 presidential elections Missouri has taken part in, it has most often sided with the Democratic party (33 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Franklin Pierce took 254 of the 296 electoral votes, against Winfield Scott's 42. Franklin Pierce led the national popular vote with 50.83% of the ballots cast.

The 1852 national map

Missouri full history →