Who won Missouri in the 1836 presidential election?

VanBuren (Democratic) carried Missouri in 1836, winning its 4 electoral votes.

How many electoral votes did Missouri have in 1836?

Missouri cast 4 electoral votes in the 1836 presidential election.

Did Missouri vote for the national winner in 1836?

No. Missouri backed VanBuren, while Martin Van Buren won the presidency nationally.

Second Party SystemMO · 4 EV

1836

Missouri: VanBuren carries 4 EV.

Missouri cast its 4 electoral votes for VanBuren (Democratic). National winner: Martin Van Buren (Democratic) — Missouri voted against the national winner this cycle.

What happened in Missouri, 1836

In 1836, Missouri awarded its 4 electoral votes to VanBuren of the Democratic party. Nationally the result broke the other way — Martin Van Buren (Democratic) won the presidency, leaving Missouri among the states he did not carry.

It marked the 3rd consecutive election in which Missouri backed the Democratic party, a streak reaching back to 1828. The region divided — Illinois and Arkansas joined Missouri for the Democratic ticket, while Kentucky and Tennessee did not. Across the 52 presidential elections Missouri has taken part in, it has most often sided with the Democratic party (33 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Martin Van Buren took 170 of the 294 electoral votes, against William Henry Harrison's 73. Martin Van Buren led the national popular vote with 50.79% of the ballots cast.

The 1836 national map

Missouri full history →