Who won Wyoming in the 1948 presidential election?

Truman (Democratic) carried Wyoming in 1948, winning its 3 electoral votes.

How many electoral votes did Wyoming have in 1948?

Wyoming cast 3 electoral votes in the 1948 presidential election.

Did Wyoming vote for the national winner in 1948?

Yes. Wyoming backed Harry S. Truman, who won the presidency that year.

New Deal CoalitionWY · 3 EV

1948

Wyoming: Truman carries 3 EV.

Wyoming cast its 3 electoral votes for Truman (Democratic). National winner: Harry S. Truman (Democratic) — Wyoming voted with the national winner this cycle.

Reading the 1948 result in Wyoming

Wyoming backed Truman (Democratic) in the 1948 presidential election, casting 3 electoral votes for the ticket. Wyoming ended up on the winning side — Harry S. Truman captured the White House that year.

It marked the 5th consecutive election in which Wyoming backed the Democratic party, a streak reaching back to 1932. The region divided — Montana, Colorado, Utah, and Idaho joined Wyoming for the Democratic ticket, while South Dakota and Nebraska did not. Across the 34 presidential elections Wyoming has taken part in, it has most often sided with the Republican party (24 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Harry S. Truman took 303 of the 531 electoral votes, against Thomas E. Dewey's 189. Harry S. Truman led the national popular vote with 49.55% of the ballots cast.

The 1948 national map

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