Who won Wyoming in the 1960 presidential election?

Kennedy (Democratic) carried Wyoming in 1960, winning its 3 electoral votes.

How many electoral votes did Wyoming have in 1960?

Wyoming cast 3 electoral votes in the 1960 presidential election.

Did Wyoming vote for the national winner in 1960?

Yes. Wyoming backed John F. Kennedy, who won the presidency that year.

New Deal CoalitionWY · 3 EV

1960

Wyoming: Kennedy carries 3 EV.

Wyoming cast its 3 electoral votes for Kennedy (Democratic). National winner: John F. Kennedy (Democratic) — Wyoming voted with the national winner this cycle.

Reading the 1960 result in Wyoming

Wyoming backed Kennedy (Democratic) in the 1960 presidential election, casting 3 electoral votes for the ticket. Wyoming ended up on the winning side — John F. Kennedy captured the White House that year.

Kennedy's win closed out Wyoming's 2-election run of voting Republican. The region divided — Montana joined Wyoming for the Democratic ticket, while South Dakota, Nebraska, Colorado, Utah, and Idaho did not. Across the 34 presidential elections Wyoming has taken part in, it has most often sided with the Republican party (24 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, John F. Kennedy took 303 of the 537 electoral votes, against Richard Nixon's 219. John F. Kennedy led the national popular vote with 49.72% of the ballots cast.

The 1960 national map

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