Who won Wyoming in the 1940 presidential election?

Roosevelt (Democratic) carried Wyoming in 1940, winning its 3 electoral votes.

How many electoral votes did Wyoming have in 1940?

Wyoming cast 3 electoral votes in the 1940 presidential election.

Did Wyoming vote for the national winner in 1940?

Yes. Wyoming backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionWY · 3 EV

1940

Wyoming: Roosevelt carries 3 EV.

Wyoming cast its 3 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Wyoming voted with the national winner this cycle.

Wyoming in 1940

The 1940 contest saw Wyoming line up behind Roosevelt, delivering 3 electoral votes to the Democratic ticket. Wyoming ended up on the winning side — Franklin D. Roosevelt captured the White House that year.

It marked the 3rd consecutive election in which Wyoming backed the Democratic party, a streak reaching back to 1932. The region divided — Montana, Colorado, Utah, and Idaho joined Wyoming for the Democratic ticket, while South Dakota and Nebraska did not. Across the 34 presidential elections Wyoming has taken part in, it has most often sided with the Republican party (24 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Franklin D. Roosevelt took 449 of the 531 electoral votes, against Wendell Willkie's 82. Franklin D. Roosevelt led the national popular vote with 54.74% of the ballots cast.

The 1940 national map

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