Who won Wyoming in the 1956 presidential election?

Eisenhower (Republican) carried Wyoming in 1956, winning its 3 electoral votes.

How many electoral votes did Wyoming have in 1956?

Wyoming cast 3 electoral votes in the 1956 presidential election.

Did Wyoming vote for the national winner in 1956?

Yes. Wyoming backed Dwight D. Eisenhower, who won the presidency that year.

New Deal CoalitionWY · 3 EV

1956

Wyoming: Eisenhower carries 3 EV.

Wyoming cast its 3 electoral votes for Eisenhower (Republican). National winner: Dwight D. Eisenhower (Republican) — Wyoming voted with the national winner this cycle.

What happened in Wyoming, 1956

In 1956, Wyoming awarded its 3 electoral votes to Eisenhower of the Republican party. That placed Wyoming with the eventual winner: Dwight D. Eisenhower went on to take the presidency, and Wyoming was part of his column.

Wyoming stayed in the Republican column for the 2nd straight cycle, extending a run that began in 1952. Wyoming did not move alone — neighboring Montana, South Dakota, Nebraska, Colorado, Utah, and Idaho broke the same way in 1956. Over its 34 recorded presidential cycles, Wyoming has backed the Republican party more than any other — 24 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Dwight D. Eisenhower finished with 457 of the 531 electoral votes to Adlai Stevenson II's 73. Dwight D. Eisenhower led the national popular vote with 57.37% of the ballots cast.

The 1956 national map

Wyoming full history →