Who won Missouri in the 1948 presidential election?

Truman (Democratic) carried Missouri in 1948, winning its 15 electoral votes.

How many electoral votes did Missouri have in 1948?

Missouri cast 15 electoral votes in the 1948 presidential election.

Did Missouri vote for the national winner in 1948?

Yes. Missouri backed Harry S. Truman, who won the presidency that year.

New Deal CoalitionMO · 15 EV

1948

Missouri: Truman carries 15 EV.

Missouri cast its 15 electoral votes for Truman (Democratic). National winner: Harry S. Truman (Democratic) — Missouri voted with the national winner this cycle.

Reading the 1948 result in Missouri

Missouri backed Truman (Democratic) in the 1948 presidential election, casting 15 electoral votes for the ticket. Missouri ended up on the winning side — Harry S. Truman captured the White House that year.

It marked the 5th consecutive election in which Missouri backed the Democratic party, a streak reaching back to 1932. The region divided — Iowa, Illinois, Kentucky, Tennessee, Arkansas, and Oklahoma joined Missouri for the Democratic ticket, while Kansas and Nebraska did not. Across the 52 presidential elections Missouri has taken part in, it has most often sided with the Democratic party (33 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Harry S. Truman took 303 of the 531 electoral votes, against Thomas E. Dewey's 189. Harry S. Truman led the national popular vote with 49.55% of the ballots cast.

The 1948 national map

Missouri full history →