Who won Oklahoma in the 1936 presidential election?

Roosevelt (Democratic) carried Oklahoma in 1936, winning its 11 electoral votes.

How many electoral votes did Oklahoma have in 1936?

Oklahoma cast 11 electoral votes in the 1936 presidential election.

Did Oklahoma vote for the national winner in 1936?

Yes. Oklahoma backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionOK · 11 EV

1936

Oklahoma: Roosevelt carries 11 EV.

Oklahoma cast its 11 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Oklahoma voted with the national winner this cycle.

Oklahoma in 1936

The 1936 contest saw Oklahoma line up behind Roosevelt, delivering 11 electoral votes to the Democratic ticket. That placed Oklahoma with the eventual winner: Franklin D. Roosevelt went on to take the presidency, and Oklahoma was part of his column.

Oklahoma stayed in the Democratic column for the 2nd straight cycle, extending a run that began in 1932. The region divided — Missouri, Arkansas, Texas, New Mexico, and Colorado joined Oklahoma for the Democratic ticket, while Kansas did not. Over its 30 recorded presidential cycles, Oklahoma has backed the Republican party more than any other — 20 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Franklin D. Roosevelt finished with 523 of the 531 electoral votes to Alf Landon's 8. Franklin D. Roosevelt led the national popular vote with 60.8% of the ballots cast.

The 1936 national map

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