Who won Oklahoma in the 1956 presidential election?

Eisenhower (Republican) carried Oklahoma in 1956, winning its 8 electoral votes.

How many electoral votes did Oklahoma have in 1956?

Oklahoma cast 8 electoral votes in the 1956 presidential election.

Did Oklahoma vote for the national winner in 1956?

Yes. Oklahoma backed Dwight D. Eisenhower, who won the presidency that year.

New Deal CoalitionOK · 8 EV

1956

Oklahoma: Eisenhower carries 8 EV.

Oklahoma cast its 8 electoral votes for Eisenhower (Republican). National winner: Dwight D. Eisenhower (Republican) — Oklahoma voted with the national winner this cycle.

Reading the 1956 result in Oklahoma

Oklahoma backed Eisenhower (Republican) in the 1956 presidential election, casting 8 electoral votes for the ticket. That placed Oklahoma with the eventual winner: Dwight D. Eisenhower went on to take the presidency, and Oklahoma was part of his column.

Oklahoma stayed in the Republican column for the 2nd straight cycle, extending a run that began in 1952. The region divided — Kansas, New Mexico, and Colorado joined Oklahoma for the Republican ticket, while Missouri, Arkansas, and Texas did not. Over its 30 recorded presidential cycles, Oklahoma has backed the Republican party more than any other — 20 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Dwight D. Eisenhower finished with 457 of the 531 electoral votes to Adlai Stevenson II's 73. Dwight D. Eisenhower led the national popular vote with 57.37% of the ballots cast.

The 1956 national map

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