Who won Oklahoma in the 1940 presidential election?

Roosevelt (Democratic) carried Oklahoma in 1940, winning its 11 electoral votes.

How many electoral votes did Oklahoma have in 1940?

Oklahoma cast 11 electoral votes in the 1940 presidential election.

Did Oklahoma vote for the national winner in 1940?

Yes. Oklahoma backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionOK · 11 EV

1940

Oklahoma: Roosevelt carries 11 EV.

Oklahoma cast its 11 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Oklahoma voted with the national winner this cycle.

What happened in Oklahoma, 1940

In 1940, Oklahoma awarded its 11 electoral votes to Roosevelt of the Democratic party. Oklahoma ended up on the winning side — Franklin D. Roosevelt captured the White House that year.

It marked the 3rd consecutive election in which Oklahoma backed the Democratic party, a streak reaching back to 1932. The region divided — Missouri, Arkansas, Texas, New Mexico, and Colorado joined Oklahoma for the Democratic ticket, while Kansas did not. Across the 30 presidential elections Oklahoma has taken part in, it has most often sided with the Republican party (20 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Franklin D. Roosevelt took 449 of the 531 electoral votes, against Wendell Willkie's 82. Franklin D. Roosevelt led the national popular vote with 54.74% of the ballots cast.

The 1940 national map

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