Who won Missouri in the 1988 presidential election?

Bush (Republican) carried Missouri in 1988, winning its 11 electoral votes.

How many electoral votes did Missouri have in 1988?

Missouri cast 11 electoral votes in the 1988 presidential election.

Did Missouri vote for the national winner in 1988?

Yes. Missouri backed George H. W. Bush, who won the presidency that year.

Cold War RealignmentMO · 11 EV

1988

Missouri: Bush carries 11 EV.

Missouri cast its 11 electoral votes for Bush (Republican). National winner: George H. W. Bush (Republican) — Missouri voted with the national winner this cycle.

Missouri in 1988

The 1988 contest saw Missouri line up behind Bush, delivering 11 electoral votes to the Republican ticket. Missouri ended up on the winning side — George H. W. Bush captured the White House that year.

It marked the 3rd consecutive election in which Missouri backed the Republican party, a streak reaching back to 1980. The region divided — Illinois, Kentucky, Tennessee, Arkansas, Oklahoma, Kansas, and Nebraska joined Missouri for the Republican ticket, while Iowa did not. Across the 52 presidential elections Missouri has taken part in, it has most often sided with the Democratic party (33 times). The vote fell within the Cold War Realignment — Nixon, Reagan, and the Republican South.

In the national count, George H. W. Bush took 426 of the 538 electoral votes, against Michael Dukakis's 111. George H. W. Bush led the national popular vote with 53.37% of the ballots cast.

The 1988 national map

Missouri full history →