Who won Missouri in the 1896 presidential election?

Bryan (Democratic) carried Missouri in 1896, winning its 17 electoral votes.

How many electoral votes did Missouri have in 1896?

Missouri cast 17 electoral votes in the 1896 presidential election.

Did Missouri vote for the national winner in 1896?

No. Missouri backed Bryan, while William McKinley won the presidency nationally.

Progressive EraMO · 17 EV

1896

Missouri: Bryan carries 17 EV.

Missouri cast its 17 electoral votes for Bryan (Democratic). National winner: William McKinley (Republican) — Missouri voted against the national winner this cycle.

What happened in Missouri, 1896

In 1896, Missouri awarded its 17 electoral votes to Bryan of the Democratic party. Nationally the result broke the other way — William McKinley (Republican) won the presidency, leaving Missouri among the states he did not carry.

It marked the 7th consecutive election in which Missouri backed the Democratic party, a streak reaching back to 1872. The region divided — Kentucky, Tennessee, Arkansas, Kansas, and Nebraska joined Missouri for the Democratic ticket, while Iowa and Illinois did not. Across the 52 presidential elections Missouri has taken part in, it has most often sided with the Democratic party (33 times). The vote fell within the Progressive Era — Trust-busting, suffrage, and World War I.

In the national count, William McKinley took 271 of the 447 electoral votes, against William Jennings Bryan's 176. William McKinley led the national popular vote with 51.02% of the ballots cast.

The 1896 national map

Missouri full history →