Who won Missouri in the 1892 presidential election?

Cleveland (Democratic) carried Missouri in 1892, winning its 17 electoral votes.

How many electoral votes did Missouri have in 1892?

Missouri cast 17 electoral votes in the 1892 presidential election.

Did Missouri vote for the national winner in 1892?

Yes. Missouri backed Grover Cleveland, who won the presidency that year.

Gilded AgeMO · 17 EV

1892

Missouri: Cleveland carries 17 EV.

Missouri cast its 17 electoral votes for Cleveland (Democratic). National winner: Grover Cleveland (Democratic) — Missouri voted with the national winner this cycle.

Missouri in 1892

The 1892 contest saw Missouri line up behind Cleveland, delivering 17 electoral votes to the Democratic ticket. Missouri ended up on the winning side — Grover Cleveland captured the White House that year.

It marked the 6th consecutive election in which Missouri backed the Democratic party, a streak reaching back to 1872. The region divided — Illinois, Kentucky, Tennessee, and Arkansas joined Missouri for the Democratic ticket, while Iowa, Kansas, and Nebraska did not. Across the 52 presidential elections Missouri has taken part in, it has most often sided with the Democratic party (33 times). The vote fell within the Gilded Age — Industrialization, narrow margins, and patronage politics.

In the national count, Grover Cleveland took 277 of the 444 electoral votes, against Benjamin Harrison's 145. Grover Cleveland led the national popular vote with 46.02% of the ballots cast.

The 1892 national map

Missouri full history →