Who won Washington in the 1956 presidential election?

Eisenhower (Republican) carried Washington in 1956, winning its 9 electoral votes.

How many electoral votes did Washington have in 1956?

Washington cast 9 electoral votes in the 1956 presidential election.

Did Washington vote for the national winner in 1956?

Yes. Washington backed Dwight D. Eisenhower, who won the presidency that year.

New Deal CoalitionWA · 9 EV

1956

Washington: Eisenhower carries 9 EV.

Washington cast its 9 electoral votes for Eisenhower (Republican). National winner: Dwight D. Eisenhower (Republican) — Washington voted with the national winner this cycle.

What happened in Washington, 1956

In 1956, Washington awarded its 9 electoral votes to Eisenhower of the Republican party. That placed Washington with the eventual winner: Dwight D. Eisenhower went on to take the presidency, and Washington was part of his column.

Washington stayed in the Republican column for the 2nd straight cycle, extending a run that began in 1952. Washington did not move alone — neighboring Oregon and Idaho broke the same way in 1956. Over its 34 recorded presidential cycles, Washington has backed the Democratic party more than any other — 19 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Dwight D. Eisenhower finished with 457 of the 531 electoral votes to Adlai Stevenson II's 73. Dwight D. Eisenhower led the national popular vote with 57.37% of the ballots cast.

The 1956 national map

Washington full history →