Who won Washington in the 1940 presidential election?

Roosevelt (Democratic) carried Washington in 1940, winning its 8 electoral votes.

How many electoral votes did Washington have in 1940?

Washington cast 8 electoral votes in the 1940 presidential election.

Did Washington vote for the national winner in 1940?

Yes. Washington backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionWA · 8 EV

1940

Washington: Roosevelt carries 8 EV.

Washington cast its 8 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Washington voted with the national winner this cycle.

Washington in 1940

The 1940 contest saw Washington line up behind Roosevelt, delivering 8 electoral votes to the Democratic ticket. Washington ended up on the winning side — Franklin D. Roosevelt captured the White House that year.

It marked the 3rd consecutive election in which Washington backed the Democratic party, a streak reaching back to 1932. Washington did not move alone — neighboring Oregon and Idaho broke the same way in 1940. Across the 34 presidential elections Washington has taken part in, it has most often sided with the Democratic party (19 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Franklin D. Roosevelt took 449 of the 531 electoral votes, against Wendell Willkie's 82. Franklin D. Roosevelt led the national popular vote with 54.74% of the ballots cast.

The 1940 national map

Washington full history →