Who won Washington in the 1936 presidential election?

Roosevelt (Democratic) carried Washington in 1936, winning its 8 electoral votes.

How many electoral votes did Washington have in 1936?

Washington cast 8 electoral votes in the 1936 presidential election.

Did Washington vote for the national winner in 1936?

Yes. Washington backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionWA · 8 EV

1936

Washington: Roosevelt carries 8 EV.

Washington cast its 8 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Washington voted with the national winner this cycle.

Reading the 1936 result in Washington

Washington backed Roosevelt (Democratic) in the 1936 presidential election, casting 8 electoral votes for the ticket. That placed Washington with the eventual winner: Franklin D. Roosevelt went on to take the presidency, and Washington was part of his column.

Washington stayed in the Democratic column for the 2nd straight cycle, extending a run that began in 1932. Washington did not move alone — neighboring Oregon and Idaho broke the same way in 1936. Over its 34 recorded presidential cycles, Washington has backed the Democratic party more than any other — 19 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Franklin D. Roosevelt finished with 523 of the 531 electoral votes to Alf Landon's 8. Franklin D. Roosevelt led the national popular vote with 60.8% of the ballots cast.

The 1936 national map

Washington full history →