Who won Minnesota in the 1948 presidential election?

Truman (Democratic) carried Minnesota in 1948, winning its 11 electoral votes.

How many electoral votes did Minnesota have in 1948?

Minnesota cast 11 electoral votes in the 1948 presidential election.

Did Minnesota vote for the national winner in 1948?

Yes. Minnesota backed Harry S. Truman, who won the presidency that year.

New Deal CoalitionMN · 11 EV

1948

Minnesota: Truman carries 11 EV.

Minnesota cast its 11 electoral votes for Truman (Democratic). National winner: Harry S. Truman (Democratic) — Minnesota voted with the national winner this cycle.

What happened in Minnesota, 1948

In 1948, Minnesota awarded its 11 electoral votes to Truman of the Democratic party. That placed Minnesota with the eventual winner: Harry S. Truman went on to take the presidency, and Minnesota was part of his column.

Minnesota stayed in the Democratic column for the 5th straight cycle, extending a run that began in 1932. The region divided — Iowa and Wisconsin joined Minnesota for the Democratic ticket, while North Dakota and South Dakota did not. Over its 43 recorded presidential cycles, Minnesota has backed the Democratic party more than any other — 23 times in all. The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

Nationally, Harry S. Truman finished with 303 of the 531 electoral votes to Thomas E. Dewey's 189. Harry S. Truman led the national popular vote with 49.55% of the ballots cast.

The 1948 national map

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