Who won Iowa in the 1904 presidential election?

Roosevelt (Republican) carried Iowa in 1904, winning its 13 electoral votes.

How many electoral votes did Iowa have in 1904?

Iowa cast 13 electoral votes in the 1904 presidential election.

Did Iowa vote for the national winner in 1904?

Yes. Iowa backed Theodore Roosevelt, who won the presidency that year.

Progressive EraIA · 13 EV

1904

Iowa: Roosevelt carries 13 EV.

Iowa cast its 13 electoral votes for Roosevelt (Republican). National winner: Theodore Roosevelt (Republican) — Iowa voted with the national winner this cycle.

What happened in Iowa, 1904

In 1904, Iowa awarded its 13 electoral votes to Roosevelt of the Republican party. Iowa ended up on the winning side — Theodore Roosevelt captured the White House that year.

It marked the 13th consecutive election in which Iowa backed the Republican party, a streak reaching back to 1856. The region divided — Minnesota, Wisconsin, Illinois, Nebraska, and South Dakota joined Iowa for the Republican ticket, while Missouri did not. Across the 47 presidential elections Iowa has taken part in, it has most often sided with the Republican party (32 times). The vote fell within the Progressive Era — Trust-busting, suffrage, and World War I.

In the national count, Theodore Roosevelt took 336 of the 476 electoral votes, against Alton B. Parker's 140. Theodore Roosevelt led the national popular vote with 56.42% of the ballots cast.

The 1904 national map

Iowa full history →