Who won Iowa in the 1888 presidential election?

Harrison (Republican) carried Iowa in 1888, winning its 13 electoral votes.

How many electoral votes did Iowa have in 1888?

Iowa cast 13 electoral votes in the 1888 presidential election.

Did Iowa vote for the national winner in 1888?

Yes. Iowa backed Benjamin Harrison, who won the presidency that year.

Gilded AgeIA · 13 EV

1888

Iowa: Harrison carries 13 EV.

Iowa cast its 13 electoral votes for Harrison (Republican). National winner: Benjamin Harrison (Republican) — Iowa voted with the national winner this cycle.

Iowa in 1888

The 1888 contest saw Iowa line up behind Harrison, delivering 13 electoral votes to the Republican ticket. That placed Iowa with the eventual winner: Benjamin Harrison went on to take the presidency, and Iowa was part of his column.

Iowa stayed in the Republican column for the 9th straight cycle, extending a run that began in 1856. The region divided — Minnesota, Wisconsin, Illinois, and Nebraska joined Iowa for the Republican ticket, while Missouri did not. Over its 47 recorded presidential cycles, Iowa has backed the Republican party more than any other — 32 times in all. The vote fell within the Gilded Age — Industrialization, narrow margins, and patronage politics.

Nationally, Benjamin Harrison finished with 233 of the 401 electoral votes to Grover Cleveland's 168. Though Benjamin Harrison won the Electoral College, Grover Cleveland drew more of the national popular vote — 48.63% to 47.8%.

The 1888 national map

Iowa full history →