Who won Iowa in the 1880 presidential election?

Garfield (Republican) carried Iowa in 1880, winning its 11 electoral votes.

How many electoral votes did Iowa have in 1880?

Iowa cast 11 electoral votes in the 1880 presidential election.

Did Iowa vote for the national winner in 1880?

Yes. Iowa backed James A. Garfield, who won the presidency that year.

Gilded AgeIA · 11 EV

1880

Iowa: Garfield carries 11 EV.

Iowa cast its 11 electoral votes for Garfield (Republican). National winner: James A. Garfield (Republican) — Iowa voted with the national winner this cycle.

What happened in Iowa, 1880

In 1880, Iowa awarded its 11 electoral votes to Garfield of the Republican party. That placed Iowa with the eventual winner: James A. Garfield went on to take the presidency, and Iowa was part of his column.

Iowa stayed in the Republican column for the 7th straight cycle, extending a run that began in 1856. The region divided — Minnesota, Wisconsin, Illinois, and Nebraska joined Iowa for the Republican ticket, while Missouri did not. Over its 47 recorded presidential cycles, Iowa has backed the Republican party more than any other — 32 times in all. The vote fell within the Gilded Age — Industrialization, narrow margins, and patronage politics.

Nationally, James A. Garfield finished with 214 of the 369 electoral votes to Winfield Scott Hancock's 155. James A. Garfield led the national popular vote with 48.31% of the ballots cast.

The 1880 national map

Iowa full history →