Who won Nebraska in the 1956 presidential election?

Eisenhower (Republican) carried Nebraska in 1956, winning its 6 electoral votes.

How many electoral votes did Nebraska have in 1956?

Nebraska cast 6 electoral votes in the 1956 presidential election.

Did Nebraska vote for the national winner in 1956?

Yes. Nebraska backed Dwight D. Eisenhower, who won the presidency that year.

New Deal CoalitionNE · 6 EV

1956

Nebraska: Eisenhower carries 6 EV.

Nebraska cast its 6 electoral votes for Eisenhower (Republican). National winner: Dwight D. Eisenhower (Republican) — Nebraska voted with the national winner this cycle.

What happened in Nebraska, 1956

In 1956, Nebraska awarded its 6 electoral votes to Eisenhower of the Republican party. Nebraska ended up on the winning side — Dwight D. Eisenhower captured the White House that year.

It marked the 5th consecutive election in which Nebraska backed the Republican party, a streak reaching back to 1940. The region divided — South Dakota, Iowa, Kansas, Colorado, and Wyoming joined Nebraska for the Republican ticket, while Missouri did not. Across the 40 presidential elections Nebraska has taken part in, it has most often sided with the Republican party (31 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Dwight D. Eisenhower took 457 of the 531 electoral votes, against Adlai Stevenson II's 73. Dwight D. Eisenhower led the national popular vote with 57.37% of the ballots cast.

The 1956 national map

Nebraska full history →