Who won Wisconsin in the 1948 presidential election?

Truman (Democratic) carried Wisconsin in 1948, winning its 12 electoral votes.

How many electoral votes did Wisconsin have in 1948?

Wisconsin cast 12 electoral votes in the 1948 presidential election.

Did Wisconsin vote for the national winner in 1948?

Yes. Wisconsin backed Harry S. Truman, who won the presidency that year.

New Deal CoalitionWI · 12 EV

1948

Wisconsin: Truman carries 12 EV.

Wisconsin cast its 12 electoral votes for Truman (Democratic). National winner: Harry S. Truman (Democratic) — Wisconsin voted with the national winner this cycle.

What happened in Wisconsin, 1948

In 1948, Wisconsin awarded its 12 electoral votes to Truman of the Democratic party. Wisconsin ended up on the winning side — Harry S. Truman captured the White House that year.

It marked the 5th consecutive election in which Wisconsin backed the Democratic party, a streak reaching back to 1932. The region divided — Minnesota, Iowa, and Illinois joined Wisconsin for the Democratic ticket, while Michigan did not. Across the 45 presidential elections Wisconsin has taken part in, it has most often sided with the Republican party (24 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Harry S. Truman took 303 of the 531 electoral votes, against Thomas E. Dewey's 189. Harry S. Truman led the national popular vote with 49.55% of the ballots cast.

The 1948 national map

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