Who won Rhode Island in the 1936 presidential election?

Roosevelt (Democratic) carried Rhode Island in 1936, winning its 4 electoral votes.

How many electoral votes did Rhode Island have in 1936?

Rhode Island cast 4 electoral votes in the 1936 presidential election.

Did Rhode Island vote for the national winner in 1936?

Yes. Rhode Island backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionRI · 4 EV

1936

Rhode Island: Roosevelt carries 4 EV.

Rhode Island cast its 4 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Rhode Island voted with the national winner this cycle.

Rhode Island in 1936

The 1936 contest saw Rhode Island line up behind Roosevelt, delivering 4 electoral votes to the Democratic ticket. Rhode Island ended up on the winning side — Franklin D. Roosevelt captured the White House that year.

It marked the 3rd consecutive election in which Rhode Island backed the Democratic party, a streak reaching back to 1928. Rhode Island did not move alone — neighboring Connecticut and Massachusetts broke the same way in 1936. Across the 59 presidential elections Rhode Island has taken part in, it has most often sided with the Democratic party (25 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Franklin D. Roosevelt took 523 of the 531 electoral votes, against Alf Landon's 8. Franklin D. Roosevelt led the national popular vote with 60.8% of the ballots cast.

The 1936 national map

Rhode Island full history →