Who won Rhode Island in the 1956 presidential election?

Eisenhower (Republican) carried Rhode Island in 1956, winning its 4 electoral votes.

How many electoral votes did Rhode Island have in 1956?

Rhode Island cast 4 electoral votes in the 1956 presidential election.

Did Rhode Island vote for the national winner in 1956?

Yes. Rhode Island backed Dwight D. Eisenhower, who won the presidency that year.

New Deal CoalitionRI · 4 EV

1956

Rhode Island: Eisenhower carries 4 EV.

Rhode Island cast its 4 electoral votes for Eisenhower (Republican). National winner: Dwight D. Eisenhower (Republican) — Rhode Island voted with the national winner this cycle.

Reading the 1956 result in Rhode Island

Rhode Island backed Eisenhower (Republican) in the 1956 presidential election, casting 4 electoral votes for the ticket. Rhode Island ended up on the winning side — Dwight D. Eisenhower captured the White House that year.

Eisenhower's win closed out Rhode Island's 7-election run of voting Democratic. Rhode Island did not move alone — neighboring Connecticut and Massachusetts broke the same way in 1956. Across the 59 presidential elections Rhode Island has taken part in, it has most often sided with the Democratic party (25 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Dwight D. Eisenhower took 457 of the 531 electoral votes, against Adlai Stevenson II's 73. Dwight D. Eisenhower led the national popular vote with 57.37% of the ballots cast.

The 1956 national map

Rhode Island full history →