Who won Washington in the 1892 presidential election?

Harrison (Republican) carried Washington in 1892, winning its 4 electoral votes.

How many electoral votes did Washington have in 1892?

Washington cast 4 electoral votes in the 1892 presidential election.

Did Washington vote for the national winner in 1892?

No. Washington backed Harrison, while Grover Cleveland won the presidency nationally.

Gilded AgeWA · 4 EV

1892

Washington: Harrison carries 4 EV.

Washington cast its 4 electoral votes for Harrison (Republican). National winner: Grover Cleveland (Democratic) — Washington voted against the national winner this cycle.

Washington in 1892

The 1892 contest saw Washington line up behind Harrison, delivering 4 electoral votes to the Republican ticket. Nationally the result broke the other way — Grover Cleveland (Democratic) won the presidency, leaving Washington among the states he did not carry.

1892 was the first presidential election in which Washington cast electoral votes. The region divided — Oregon joined Washington for the Republican ticket, while Idaho did not. Across the 34 presidential elections Washington has taken part in, it has most often sided with the Democratic party (19 times). The vote fell within the Gilded Age — Industrialization, narrow margins, and patronage politics.

In the national count, Grover Cleveland took 277 of the 444 electoral votes, against Benjamin Harrison's 145. Grover Cleveland led the national popular vote with 46.02% of the ballots cast.

The 1892 national map

Washington full history →