Who won Missouri in the 1828 presidential election?

Jackson (Democratic) carried Missouri in 1828, winning its 3 electoral votes.

How many electoral votes did Missouri have in 1828?

Missouri cast 3 electoral votes in the 1828 presidential election.

Did Missouri vote for the national winner in 1828?

Yes. Missouri backed Andrew Jackson, who won the presidency that year.

Second Party SystemMO · 3 EV

1828

Missouri: Jackson carries 3 EV.

Missouri cast its 3 electoral votes for Jackson (Democratic). National winner: Andrew Jackson (Democratic) — Missouri voted with the national winner this cycle.

Reading the 1828 result in Missouri

Missouri backed Jackson (Democratic) in the 1828 presidential election, casting 3 electoral votes for the ticket. That placed Missouri with the eventual winner: Andrew Jackson went on to take the presidency, and Missouri was part of his column.

The result flipped Missouri away from the Democratic-Republican ticket it had backed in each of the previous 2 cycles. Missouri did not move alone — neighboring Illinois, Kentucky, and Tennessee broke the same way in 1828. Over its 52 recorded presidential cycles, Missouri has backed the Democratic party more than any other — 33 times in all. The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

Nationally, Andrew Jackson finished with 178 of the 261 electoral votes to John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Missouri full history →