Who won Ohio in the 1828 presidential election?

Jackson (Democratic) carried Ohio in 1828, winning its 16 electoral votes.

How many electoral votes did Ohio have in 1828?

Ohio cast 16 electoral votes in the 1828 presidential election.

Did Ohio vote for the national winner in 1828?

Yes. Ohio backed Andrew Jackson, who won the presidency that year.

Second Party SystemOH · 16 EV

1828

Ohio: Jackson carries 16 EV.

Ohio cast its 16 electoral votes for Jackson (Democratic). National winner: Andrew Jackson (Democratic) — Ohio voted with the national winner this cycle.

Ohio in 1828

The 1828 contest saw Ohio line up behind Jackson, delivering 16 electoral votes to the Democratic ticket. Ohio ended up on the winning side — Andrew Jackson captured the White House that year.

Jackson's win closed out Ohio's 6-election run of voting Democratic-Republican. The region divided — Indiana, Kentucky, and Pennsylvania joined Ohio for the Democratic ticket, while Michigan did not. Across the 56 presidential elections Ohio has taken part in, it has most often sided with the Republican party (30 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Andrew Jackson took 178 of the 261 electoral votes, against John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Ohio full history →