Who won Connecticut in the 1828 presidential election?

Adams (Democratic-Republican) carried Connecticut in 1828, winning its 8 electoral votes.

How many electoral votes did Connecticut have in 1828?

Connecticut cast 8 electoral votes in the 1828 presidential election.

Did Connecticut vote for the national winner in 1828?

No. Connecticut backed Adams, while Andrew Jackson won the presidency nationally.

Second Party SystemCT · 8 EV

1828

Connecticut: Adams carries 8 EV.

Connecticut cast its 8 electoral votes for Adams (Democratic-Republican). National winner: Andrew Jackson (Democratic) — Connecticut voted against the national winner this cycle.

Reading the 1828 result in Connecticut

Connecticut backed Adams (Democratic-Republican) in the 1828 presidential election, casting 8 electoral votes for the ticket. Nationally the result broke the other way — Andrew Jackson (Democratic) won the presidency, leaving Connecticut among the states he did not carry.

It marked the 3rd consecutive election in which Connecticut backed the Democratic-Republican party, a streak reaching back to 1820. The region divided — Massachusetts and Rhode Island joined Connecticut for the Democratic-Republican ticket, while New York did not. Across the 60 presidential elections Connecticut has taken part in, it has most often sided with the Democratic party (24 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Andrew Jackson took 178 of the 261 electoral votes, against John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

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