Who won Washington in the 1988 presidential election?

Dukakis (Democratic) carried Washington in 1988, winning its 10 electoral votes.

How many electoral votes did Washington have in 1988?

Washington cast 10 electoral votes in the 1988 presidential election.

Did Washington vote for the national winner in 1988?

No. Washington backed Dukakis, while George H. W. Bush won the presidency nationally.

Cold War RealignmentWA · 10 EV

1988

Washington: Dukakis carries 10 EV.

Washington cast its 10 electoral votes for Dukakis (Democratic). National winner: George H. W. Bush (Republican) — Washington voted against the national winner this cycle.

Washington in 1988

The 1988 contest saw Washington line up behind Dukakis, delivering 10 electoral votes to the Democratic ticket. Nationally the result broke the other way — George H. W. Bush (Republican) won the presidency, leaving Washington among the states he did not carry.

Dukakis's win closed out Washington's 4-election run of voting Republican. The region divided — Oregon joined Washington for the Democratic ticket, while Idaho did not. Across the 34 presidential elections Washington has taken part in, it has most often sided with the Democratic party (19 times). The vote fell within the Cold War Realignment — Nixon, Reagan, and the Republican South.

In the national count, George H. W. Bush took 426 of the 538 electoral votes, against Michael Dukakis's 111. George H. W. Bush led the national popular vote with 53.37% of the ballots cast.

The 1988 national map

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