Who won Oklahoma in the 1988 presidential election?

Bush (Republican) carried Oklahoma in 1988, winning its 8 electoral votes.

How many electoral votes did Oklahoma have in 1988?

Oklahoma cast 8 electoral votes in the 1988 presidential election.

Did Oklahoma vote for the national winner in 1988?

Yes. Oklahoma backed George H. W. Bush, who won the presidency that year.

Cold War RealignmentOK · 8 EV

1988

Oklahoma: Bush carries 8 EV.

Oklahoma cast its 8 electoral votes for Bush (Republican). National winner: George H. W. Bush (Republican) — Oklahoma voted with the national winner this cycle.

What happened in Oklahoma, 1988

In 1988, Oklahoma awarded its 8 electoral votes to Bush of the Republican party. Oklahoma ended up on the winning side — George H. W. Bush captured the White House that year.

It marked the 6th consecutive election in which Oklahoma backed the Republican party, a streak reaching back to 1968. Oklahoma did not move alone — neighboring Kansas, Missouri, Arkansas, Texas, New Mexico, and Colorado broke the same way in 1988. Across the 30 presidential elections Oklahoma has taken part in, it has most often sided with the Republican party (20 times). The vote fell within the Cold War Realignment — Nixon, Reagan, and the Republican South.

In the national count, George H. W. Bush took 426 of the 538 electoral votes, against Michael Dukakis's 111. George H. W. Bush led the national popular vote with 53.37% of the ballots cast.

The 1988 national map

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