Who won Arkansas in the 1956 presidential election?

Stevenson (Democratic) carried Arkansas in 1956, winning its 8 electoral votes.

How many electoral votes did Arkansas have in 1956?

Arkansas cast 8 electoral votes in the 1956 presidential election.

Did Arkansas vote for the national winner in 1956?

No. Arkansas backed Stevenson, while Dwight D. Eisenhower won the presidency nationally.

New Deal CoalitionAR · 8 EV

1956

Arkansas: Stevenson carries 8 EV.

Arkansas cast its 8 electoral votes for Stevenson (Democratic). National winner: Dwight D. Eisenhower (Republican) — Arkansas voted against the national winner this cycle.

What happened in Arkansas, 1956

In 1956, Arkansas awarded its 8 electoral votes to Stevenson of the Democratic party. Nationally the result broke the other way — Dwight D. Eisenhower (Republican) won the presidency, leaving Arkansas among the states he did not carry.

It marked the 21st consecutive election in which Arkansas backed the Democratic party, a streak reaching back to 1876. The region divided — Missouri, Mississippi, Louisiana, and Texas joined Arkansas for the Democratic ticket, while Tennessee and Oklahoma did not. Across the 47 presidential elections Arkansas has taken part in, it has most often sided with the Democratic party (32 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Dwight D. Eisenhower took 457 of the 531 electoral votes, against Adlai Stevenson II's 73. Dwight D. Eisenhower led the national popular vote with 57.37% of the ballots cast.

The 1956 national map

Arkansas full history →