Who won Oregon in the 1936 presidential election?

Roosevelt (Democratic) carried Oregon in 1936, winning its 5 electoral votes.

How many electoral votes did Oregon have in 1936?

Oregon cast 5 electoral votes in the 1936 presidential election.

Did Oregon vote for the national winner in 1936?

Yes. Oregon backed Franklin D. Roosevelt, who won the presidency that year.

New Deal CoalitionOR · 5 EV

1936

Oregon: Roosevelt carries 5 EV.

Oregon cast its 5 electoral votes for Roosevelt (Democratic). National winner: Franklin D. Roosevelt (Democratic) — Oregon voted with the national winner this cycle.

What happened in Oregon, 1936

In 1936, Oregon awarded its 5 electoral votes to Roosevelt of the Democratic party. Oregon ended up on the winning side — Franklin D. Roosevelt captured the White House that year.

It marked the 2nd consecutive election in which Oregon backed the Democratic party, a streak reaching back to 1932. Oregon did not move alone — neighboring Washington, Idaho, Nevada, and California broke the same way in 1936. Across the 42 presidential elections Oregon has taken part in, it has most often sided with the Republican party (23 times). The vote fell within the New Deal Coalition — FDR, civil rights, and the long Democratic majority.

In the national count, Franklin D. Roosevelt took 523 of the 531 electoral votes, against Alf Landon's 8. Franklin D. Roosevelt led the national popular vote with 60.8% of the ballots cast.

The 1936 national map

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