Who won Rhode Island in the 1896 presidential election?

McKinley (Republican) carried Rhode Island in 1896, winning its 4 electoral votes.

How many electoral votes did Rhode Island have in 1896?

Rhode Island cast 4 electoral votes in the 1896 presidential election.

Did Rhode Island vote for the national winner in 1896?

Yes. Rhode Island backed William McKinley, who won the presidency that year.

Progressive EraRI · 4 EV

1896

Rhode Island: McKinley carries 4 EV.

Rhode Island cast its 4 electoral votes for McKinley (Republican). National winner: William McKinley (Republican) — Rhode Island voted with the national winner this cycle.

Reading the 1896 result in Rhode Island

Rhode Island backed McKinley (Republican) in the 1896 presidential election, casting 4 electoral votes for the ticket. That placed Rhode Island with the eventual winner: William McKinley went on to take the presidency, and Rhode Island was part of his column.

Rhode Island stayed in the Republican column for the 11th straight cycle, extending a run that began in 1856. Rhode Island did not move alone — neighboring Connecticut and Massachusetts broke the same way in 1896. Over its 59 recorded presidential cycles, Rhode Island has backed the Democratic party more than any other — 25 times in all. The vote fell within the Progressive Era — Trust-busting, suffrage, and World War I.

Nationally, William McKinley finished with 271 of the 447 electoral votes to William Jennings Bryan's 176. William McKinley led the national popular vote with 51.02% of the ballots cast.

The 1896 national map

Rhode Island full history →