Who won Iowa in the 1852 presidential election?

Pierce (Democratic) carried Iowa in 1852, winning its 4 electoral votes.

How many electoral votes did Iowa have in 1852?

Iowa cast 4 electoral votes in the 1852 presidential election.

Did Iowa vote for the national winner in 1852?

Yes. Iowa backed Franklin Pierce, who won the presidency that year.

Second Party SystemIA · 4 EV

1852

Iowa: Pierce carries 4 EV.

Iowa cast its 4 electoral votes for Pierce (Democratic). National winner: Franklin Pierce (Democratic) — Iowa voted with the national winner this cycle.

Iowa in 1852

The 1852 contest saw Iowa line up behind Pierce, delivering 4 electoral votes to the Democratic ticket. Iowa ended up on the winning side — Franklin Pierce captured the White House that year.

It marked the 4th consecutive election in which Iowa backed the Democratic party, a streak reaching back to 1840. Iowa did not move alone — neighboring Wisconsin, Illinois, and Missouri broke the same way in 1852. Across the 47 presidential elections Iowa has taken part in, it has most often sided with the Republican party (32 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Franklin Pierce took 254 of the 296 electoral votes, against Winfield Scott's 42. Franklin Pierce led the national popular vote with 50.83% of the ballots cast.

The 1852 national map

Iowa full history →