Who won Pennsylvania in the 1828 presidential election?

Jackson (Democratic) carried Pennsylvania in 1828, winning its 28 electoral votes.

How many electoral votes did Pennsylvania have in 1828?

Pennsylvania cast 28 electoral votes in the 1828 presidential election.

Did Pennsylvania vote for the national winner in 1828?

Yes. Pennsylvania backed Andrew Jackson, who won the presidency that year.

Second Party SystemPA · 28 EV

1828

Pennsylvania: Jackson carries 28 EV.

Pennsylvania cast its 28 electoral votes for Jackson (Democratic). National winner: Andrew Jackson (Democratic) — Pennsylvania voted with the national winner this cycle.

Pennsylvania in 1828

The 1828 contest saw Pennsylvania line up behind Jackson, delivering 28 electoral votes to the Democratic ticket. Pennsylvania ended up on the winning side — Andrew Jackson captured the White House that year.

Jackson's win closed out Pennsylvania's 8-election run of voting Democratic-Republican. The region divided — Ohio, Maryland, New Jersey, and New York joined Pennsylvania for the Democratic ticket, while Delaware did not. Across the 60 presidential elections Pennsylvania has taken part in, it has most often sided with the Republican party (26 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Andrew Jackson took 178 of the 261 electoral votes, against John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Pennsylvania full history →