Who won New York in the 1828 presidential election?

Jackson (Democratic) carried New York in 1828, winning its 20 electoral votes.

How many electoral votes did New York have in 1828?

New York cast 20 electoral votes in the 1828 presidential election.

Did New York vote for the national winner in 1828?

Yes. New York backed Andrew Jackson, who won the presidency that year.

Second Party SystemNY · 20 EV

1828

New York: Jackson carries 20 EV.

New York cast its 20 electoral votes for Jackson (Democratic). National winner: Andrew Jackson (Democratic) — New York voted with the national winner this cycle.

What happened in New York, 1828

In 1828, New York awarded its 20 electoral votes to Jackson of the Democratic party. New York ended up on the winning side — Andrew Jackson captured the White House that year.

Jackson's win closed out New York's 3-election run of voting Democratic-Republican. The region divided — Pennsylvania and New Jersey joined New York for the Democratic ticket, while Connecticut, Massachusetts, and Vermont did not. Across the 60 presidential elections New York has taken part in, it has most often sided with the Democratic party (29 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Andrew Jackson took 178 of the 261 electoral votes, against John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

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