Who won Indiana in the 1828 presidential election?

Jackson (Democratic) carried Indiana in 1828, winning its 5 electoral votes.

How many electoral votes did Indiana have in 1828?

Indiana cast 5 electoral votes in the 1828 presidential election.

Did Indiana vote for the national winner in 1828?

Yes. Indiana backed Andrew Jackson, who won the presidency that year.

Second Party SystemIN · 5 EV

1828

Indiana: Jackson carries 5 EV.

Indiana cast its 5 electoral votes for Jackson (Democratic). National winner: Andrew Jackson (Democratic) — Indiana voted with the national winner this cycle.

What happened in Indiana, 1828

In 1828, Indiana awarded its 5 electoral votes to Jackson of the Democratic party. Indiana ended up on the winning side — Andrew Jackson captured the White House that year.

Jackson's win closed out Indiana's 3-election run of voting Democratic-Republican. The region divided — Illinois, Kentucky, and Ohio joined Indiana for the Democratic ticket, while Michigan did not. Across the 53 presidential elections Indiana has taken part in, it has most often sided with the Republican party (32 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Andrew Jackson took 178 of the 261 electoral votes, against John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Indiana full history →