Who won Georgia in the 1828 presidential election?

Jackson (Democratic) carried Georgia in 1828, winning its 9 electoral votes.

How many electoral votes did Georgia have in 1828?

Georgia cast 9 electoral votes in the 1828 presidential election.

Did Georgia vote for the national winner in 1828?

Yes. Georgia backed Andrew Jackson, who won the presidency that year.

Second Party SystemGA · 9 EV

1828

Georgia: Jackson carries 9 EV.

Georgia cast its 9 electoral votes for Jackson (Democratic). National winner: Andrew Jackson (Democratic) — Georgia voted with the national winner this cycle.

What happened in Georgia, 1828

In 1828, Georgia awarded its 9 electoral votes to Jackson of the Democratic party. That placed Georgia with the eventual winner: Andrew Jackson went on to take the presidency, and Georgia was part of his column.

The result flipped Georgia away from the Democratic-Republican ticket it had backed in each of the previous 8 cycles. Georgia did not move alone — neighboring Alabama, Tennessee, North Carolina, and South Carolina broke the same way in 1828. Over its 59 recorded presidential cycles, Georgia has backed the Democratic party more than any other — 34 times in all. The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

Nationally, Andrew Jackson finished with 178 of the 261 electoral votes to John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Georgia full history →