Who won Rhode Island in the 1804 presidential election?

Jefferson (Democratic-Republican) carried Rhode Island in 1804, winning its 4 electoral votes.

How many electoral votes did Rhode Island have in 1804?

Rhode Island cast 4 electoral votes in the 1804 presidential election.

Did Rhode Island vote for the national winner in 1804?

Yes. Rhode Island backed Thomas Jefferson, who won the presidency that year.

First Party SystemRI · 4 EV

1804

Rhode Island: Jefferson carries 4 EV.

Rhode Island cast its 4 electoral votes for Jefferson (Democratic-Republican). National winner: Thomas Jefferson (Democratic-Republican) — Rhode Island voted with the national winner this cycle.

Rhode Island in 1804

The 1804 contest saw Rhode Island line up behind Jefferson, delivering 4 electoral votes to the Democratic-Republican ticket. Rhode Island ended up on the winning side — Thomas Jefferson captured the White House that year.

Jefferson's win closed out Rhode Island's 2-election run of voting Federalist. It stood apart from its neighbors: Connecticut and Massachusetts went the other way that year. Across the 59 presidential elections Rhode Island has taken part in, it has most often sided with the Democratic party (25 times). The vote fell within the First Party System — Federalists vs Democratic-Republicans.

In the national count, Thomas Jefferson took 162 of the 176 electoral votes, against Charles C. Pinckney's 14.

The 1804 national map

Rhode Island full history →