Who won Rhode Island in the 1792 presidential election?

Washington (Independent) carried Rhode Island in 1792, winning its 4 electoral votes.

How many electoral votes did Rhode Island have in 1792?

Rhode Island cast 4 electoral votes in the 1792 presidential election.

Did Rhode Island vote for the national winner in 1792?

Yes. Rhode Island backed George Washington, who won the presidency that year.

First Party SystemRI · 4 EV

1792

Rhode Island: Washington carries 4 EV.

Rhode Island cast its 4 electoral votes for Washington (Independent). National winner: George Washington (Independent) — Rhode Island voted with the national winner this cycle.

Rhode Island in 1792

The 1792 contest saw Rhode Island line up behind Washington, delivering 4 electoral votes to the Independent ticket. Rhode Island ended up on the winning side — George Washington captured the White House that year.

1792 was the first presidential election in which Rhode Island cast electoral votes. Rhode Island did not move alone — neighboring Connecticut and Massachusetts broke the same way in 1792. Across the 59 presidential elections Rhode Island has taken part in, it has most often sided with the Democratic party (25 times). The vote fell within the First Party System — Federalists vs Democratic-Republicans.

In the national count, George Washington took 132 of the 264 electoral votes, against John Adams's 77.

The 1792 national map

Rhode Island full history →