Who won Vermont in the 1832 presidential election?

Clay (National Republican) carried Vermont in 1832, winning its 7 electoral votes.

How many electoral votes did Vermont have in 1832?

Vermont cast 7 electoral votes in the 1832 presidential election.

Did Vermont vote for the national winner in 1832?

No. Vermont backed Clay, while Andrew Jackson won the presidency nationally.

Second Party SystemVT · 7 EV

1832

Vermont: Clay carries 7 EV.

Vermont cast its 7 electoral votes for Clay (National Republican). National winner: Andrew Jackson (Democratic) — Vermont voted against the national winner this cycle.

Vermont in 1832

The 1832 contest saw Vermont line up behind Clay, delivering 7 electoral votes to the National Republican ticket. Nationally the result broke the other way — Andrew Jackson (Democratic) won the presidency, leaving Vermont among the states he did not carry.

Clay's win closed out Vermont's 7-election run of voting Democratic-Republican. The region divided — Massachusetts joined Vermont for the National Republican ticket, while New York and New Hampshire did not. Across the 59 presidential elections Vermont has taken part in, it has most often sided with the Republican party (33 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Andrew Jackson took 219 of the 286 electoral votes, against Henry Clay's 49. Andrew Jackson led the national popular vote with 54.74% of the ballots cast.

The 1832 national map

Vermont full history →