Who won Rhode Island in the 1828 presidential election?

Adams (Democratic-Republican) carried Rhode Island in 1828, winning its 4 electoral votes.

How many electoral votes did Rhode Island have in 1828?

Rhode Island cast 4 electoral votes in the 1828 presidential election.

Did Rhode Island vote for the national winner in 1828?

No. Rhode Island backed Adams, while Andrew Jackson won the presidency nationally.

Second Party SystemRI · 4 EV

1828

Rhode Island: Adams carries 4 EV.

Rhode Island cast its 4 electoral votes for Adams (Democratic-Republican). National winner: Andrew Jackson (Democratic) — Rhode Island voted against the national winner this cycle.

Rhode Island in 1828

The 1828 contest saw Rhode Island line up behind Adams, delivering 4 electoral votes to the Democratic-Republican ticket. Nationally the result broke the other way — Andrew Jackson (Democratic) won the presidency, leaving Rhode Island among the states he did not carry.

It marked the 3rd consecutive election in which Rhode Island backed the Democratic-Republican party, a streak reaching back to 1820. Rhode Island did not move alone — neighboring Connecticut and Massachusetts broke the same way in 1828. Across the 59 presidential elections Rhode Island has taken part in, it has most often sided with the Democratic party (25 times). The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

In the national count, Andrew Jackson took 178 of the 261 electoral votes, against John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Rhode Island full history →