Who won Michigan in the 1828 presidential election?

Adams (Democratic-Republican) carried Michigan in 1828, winning its 3 electoral votes.

How many electoral votes did Michigan have in 1828?

Michigan cast 3 electoral votes in the 1828 presidential election.

Did Michigan vote for the national winner in 1828?

No. Michigan backed Adams, while Andrew Jackson won the presidency nationally.

Second Party SystemMI · 3 EV

1828

Michigan: Adams carries 3 EV.

Michigan cast its 3 electoral votes for Adams (Democratic-Republican). National winner: Andrew Jackson (Democratic) — Michigan voted against the national winner this cycle.

Reading the 1828 result in Michigan

Michigan backed Adams (Democratic-Republican) in the 1828 presidential election, casting 3 electoral votes for the ticket. The presidency went elsewhere: Andrew Jackson (Democratic) won nationally, while Michigan had backed a different ticket.

Michigan stayed in the Democratic-Republican column for the 2nd straight cycle, extending a run that began in 1824. It stood apart from its neighbors: Indiana and Ohio went the other way that year. Over its 51 recorded presidential cycles, Michigan has backed the Republican party more than any other — 28 times in all. The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

Nationally, Andrew Jackson finished with 178 of the 261 electoral votes to John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Michigan full history →