Who won Kentucky in the 1828 presidential election?

Jackson (Democratic) carried Kentucky in 1828, winning its 14 electoral votes.

How many electoral votes did Kentucky have in 1828?

Kentucky cast 14 electoral votes in the 1828 presidential election.

Did Kentucky vote for the national winner in 1828?

Yes. Kentucky backed Andrew Jackson, who won the presidency that year.

Second Party SystemKY · 14 EV

1828

Kentucky: Jackson carries 14 EV.

Kentucky cast its 14 electoral votes for Jackson (Democratic). National winner: Andrew Jackson (Democratic) — Kentucky voted with the national winner this cycle.

What happened in Kentucky, 1828

In 1828, Kentucky awarded its 14 electoral votes to Jackson of the Democratic party. That placed Kentucky with the eventual winner: Andrew Jackson went on to take the presidency, and Kentucky was part of his column.

The result flipped Kentucky away from the Democratic-Republican ticket it had backed in each of the previous 8 cycles. Kentucky did not move alone — neighboring Indiana, Ohio, Virginia, Tennessee, Missouri, and Illinois broke the same way in 1828. Over its 59 recorded presidential cycles, Kentucky has backed the Democratic party more than any other — 28 times in all. The vote fell within the Second Party System — Jackson, Whigs, and the rise of mass politics.

Nationally, Andrew Jackson finished with 178 of the 261 electoral votes to John Quincy Adams's 83. Andrew Jackson led the national popular vote with 55.93% of the ballots cast.

The 1828 national map

Kentucky full history →